ABC is an equilateral triangle. Points D, E and F are taken as the mid-point on sides AB, BC, CA respectively, so that AD = BE = CF. Then AE, BF, CD enclosed a triangle which is:
A. equilateral
B. isosceles triangle
C. right angle triangle
D. None of these
Answer: Option A
Solution (By Examveda Team)

Given in question AD = BE = CF
[DB = AF = EC] Because AB = BC = CA
So, Triangle is equilateral
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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