ABC is an equilateral triangle with side 12 cm and AD is the median. Find the length of GD is G is the centroid of ΔABC.

Solution (By Examveda Team)

$$\eqalign{ & {\text{AD}} = \frac{{\sqrt 3 }}{2} \times {\text{Side}} \cr & {\text{AD}} = \frac{{\sqrt 3 }}{2} \times 12 = 6\sqrt 3 \cr & {\text{GD}} = 6\sqrt 3 \times \frac{1}{3} = 2\sqrt 3 {\text{ cm}} \cr} $$