a, b, c, d and e are five natural numbers. Find the number of ordered sets (a, b, c, d, e) possible such that a + b + c + d + e = 64.
A. 64C5
B. 63C4
C. 65C4
D. 63C5
Answer: Option B
Solution(By Examveda Team)
Let assume that there are 64 identical balls which are to be arranged in 5 different compartments (Since a, b, c, d, e are distinguishable) If the balls are arranged in a row i.e., o, o, o, o, o, o . . . . (64 balls). We have 63 gaps where we can place a wall in each gap, since we need 5 compartments we need to place only 4 walls. We can do this in 63C4 ways.Join The Discussion
Comments ( 1 )
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what if a restriction is given that a>5,b>6 and c>7 then what extra needs to be substracted?