ABCD is a cyclic quadrilateral Diagonals BD and AC intersect each other at E. If ∠BEC = 128° and ∠ECD = 25°, then, what is the measure of ∠BAC?
A. 98°
B. 52°
C. 93°
D. 103°
Answer: Option D
Solution (By Examveda Team)
∠EDC + ∠DCF = ∠CEB
∠EDC + 25° = 128°
∠EDC = 103°
∠EDC = ∠BAC (all angles are equal same sector)
∠BAC = 103°
This Question Belongs to Arithmetic Ability >> Geometry
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