ABCD is a cyclic quadrilateral. Side AB and DC, when produced, meet at E and sides AD and BC when produced, meet at F. If ∠ADC = 76° and ∠AED = 55°, then ∠AFB is equal to:

Solution (By Examveda Team)

∠ADC = 76° ; ∠AED = 55°
∠ADC + ∠ABC = 180°
[cyclic quadrilateral]
∠ABC = 180° - 76° = 104°
In ΔADE
∠A + ∠D + ∠E = 180°
∠A = 180° - 76° - 55° = 49°
In ΔABF
∠A + ∠B + ∠F = 180°
∠F = 180° - 104° - 49° = 27°