ABCD is a square and ΔMAB is an equilateral triangle. MC and MD are joined. What is the degree measure of ∠MDC?

A. 78°
B. 60°
C. 65°
D. 75°
Answer: Option D
Solution (By Examveda Team)

∠A = ∠B = ∠D = ∠C = 90°
ΔAMB is equilateral
Hence ∠A = 60°
∠DAM = 90° + 60° = 150°
∠ADM $$ = \frac{{{{180}^ \circ } - {{150}^ \circ }}}{2} = \frac{{{{30}^ \circ }}}{2} = {15^ \circ }$$
∠MDC = 90° - 15° = 75°
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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