According to Baye's theorem, conditional probability is equal to
A. $$\frac{{P\left( {{E_i}} \right).P\left( {A/{E_i}} \right)}}{{\sum\limits_{i = 1}^n {P\left( {{E_i}} \right).P\left( {A/{E_i}} \right)} }}$$
B. $$\frac{{P\left( {A/{E_i}} \right)}}{{\sum\limits_{i = 1}^n {P\left( {{E_1}} \right).P\left( {A/{E_i}} \right)} }}$$
C. $$\frac{{P\left( {{E_i}/A} \right).P\left( {{E_i}} \right)}}{{\sum\limits_{i = 1}^n {P\left( {{E_i}} \right)} }}$$
D. $$\frac{{P\left( {{E_i}/A} \right)}}{{\sum\limits_{i = 1}^n {\left( {{E_i}} \right)} }}$$
Answer: Option A
This Question Belongs to Commerce >> Business Statistics And Research Methods
Join The Discussion