According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)
A. $$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
B. $$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
C. $$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
D. $$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
Answer: Option B

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