According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $${I_{\text{P}}}$$) is given by (where, A = Area of the section, $${I_{\text{G}}}$$ = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)
A. $${I_{\text{P}}} = {I_{\text{G}}} + {\text{A}}{{\text{h}}^2}$$
B. $${I_{\text{P}}} = {I_{\text{G}}} - {\text{A}}{{\text{h}}^2}$$
C. $${I_{\text{P}}} = \frac{{{I_{\text{G}}}}}{{{\text{A}}{{\text{h}}^2}}}$$
D. $${I_{\text{P}}} = \frac{{{\text{A}}{{\text{h}}^2}}}{{{I_{\text{G}}}}}$$
Answer: Option A

MI for Square section is
a) b/12
b) bd/12 c) 6/12
d None