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According to parallel axis theorem the moment of inertia of a...

This question belongs to Mechanical Engineering Engineering Mechanics
Engineering Mechanics
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According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $${I_{\text{P}}}$$) is given by (where, A = Area of the section, $${I_{\text{G}}}$$ = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)

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Correct Answer: Option A
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1 Comment
Sagar Chavan
Sagar Chavan 6 years ago
MI for Square section is

a) b/12

b) bd/12 c) 6/12

d None
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