After covering a distance of 30 km with a uniform speed there is some defect in a train engine and therefore, its speed is reduced to 4/5th of its original speed. Consequently, the train reaches its destination late by 45 minutes. Had it happened after covering 18 kilometers more, the train would have reached 9 minutes earlier. Find the speed of the train and the distance of journey?
A. 30 Kmph
B. 45 Kmph
C. 50 Kmph
D. 60 Kmph
E. None of these
Answer: Option A
Solution (By Examveda Team)
Train proceeds at 4/5 S where S is his usual speed means 1/5 decrease in speed which will lead to 1/4 increase in time.
Now the main difference comes in those extra 18km and the change in difference of time = (45-36) min = 9 min.
Thus,
1/4*T = 9 min where T is the time required to cover the distance of 18 km.
T = 36 min = 36 /60 hours = 0.6 hours.
Speed of the Train = 18/0.6 = 30 kmph.
This Question Belongs to User Ask Question >> Miscellaneous
good answer