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An ammeter has an internal resistance of 50 Ω. The meter movement itself can handle up to 1 mA. If 10 mA is applied to the meter, the shunt resistor, RSH1, is approximately

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Correct Answer: Option B
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1 Comment
Engr Farman
Engr Farman 6 years ago
Va = Ia.Ra= 1mA . 50 ohm
Va= 50 mv
Vsh = Ish . Rsh
Rsh = Vsh/Ish
= 50mv/ (10mA - 1mA)