An electron with energy E is incident from left on a potential barrier, given by \[\begin{gathered}
V\left( x \right) = 0{\text{ for }}x < 0 \hfill \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = {V_0}{\text{ for }}x > 0 \hfill \\
\end{gathered} \] as shown in the figure.

For E < V0, the space part of the wave function for x > 0 is of the form
A. eαx
B. e-αx
C. eiαx
D. e-iαx
Answer: Option B
Related Questions on Quantum Mechanics
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above

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