An OPAMP has a slew rate of 5 V/μS. The largest sine wave output voltage possible at a frequency of 1 MHZ is
[Hint: Slew rate is defined as the max. rate of change of output voltage. Its unit is V/μS.]
A. $$10\pi {\text{V}}$$
B. $$5{\text{V}}$$
C. $$\frac{5}{\prod }{\text{V}}$$
D. $$\frac{5}{{2\prod }}{\text{V}}$$
Answer: Option D
This Question Belongs to Electrical Engineering >> OP Amp
I'm getting 5v.
Isn't slew rate the maximum voltage change possible per second(or here us).
So the maximum change in voltage the sin wave can have is 5v/us.
if i differentiate the sin wave( A*sin(10^6*t) ):
I get A*10^6cos(10^6*t)
The maximum change in voltage is when cos()=1.
Thus,
A*10^6
5/2pi
formula is
SR = 2 * pi * f * Vo
Idiot answer is 5/2pi
how the maximum output voltage is calculated