An unitary matrix \[\left[ {\begin{array}{*{20}{c}} {a{e^{i\alpha }}}&b \\ {c{e^{i\beta }}}&d \end{array}} \right]\] is given, were a, b, c, d, α and β are real. The inverse of the matrix is
A. \[\left[ {\begin{array}{*{20}{c}} {a{e^{i\alpha }}}&{ - c{e^{i\beta }}} \\ b&d \end{array}} \right]\]
B. \[\left[ {\begin{array}{*{20}{c}} {a{e^{i\alpha }}}&{c{e^{i\beta }}} \\ b&d \end{array}} \right]\]
C. \[\left[ {\begin{array}{*{20}{c}} {a{e^{ - i\alpha }}}&b \\ {c{e^{ - i\beta }}}&d \end{array}} \right]\]
D. \[\left[ {\begin{array}{*{20}{c}} {a{e^{ - i\alpha }}}&{c{e^{ - i\beta }}} \\ b&d \end{array}} \right]\]
Answer: Option D


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