Answer & Solution
Answer: Option A
Solution:
The third term t
3 = a + 2d
The ninth term t
9 = a + 8d
t
3 + t
9 = 2a + 10d = 8
Sum of first 11 terms of an AP is given by
$$\eqalign{
& \Rightarrow {S_{11}} = \frac{{11}}{2}\left[ {2a + 10d} \right] \cr
& \Rightarrow {S_{11}} = \frac{{11}}{2} \times 8 \cr
& \Rightarrow {S_{11}} = 44 \cr} $$