51. If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is
52. The first and last terms of an A.P. are 1 and 11. If the sum of its terms is 36, then the number of terms will be
53. Let S denotes the sum of n terms of an A.P. whose first term is a. If the common difference d is given by d = Sn – k Sn-1 + Sn-2 then k =
54. If in an A.P., Sn = n2p and Sm = m2p, where S denotes the sum of r terms of the A.P., then Sp is equal to
55. The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is
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