Arrange these places in decreasing order of their atmospheric pressure on their ground surface:
1. Shimla
2. Gangtok
3. Mumbai
4. Delhi
A. 3, 4, 1, 2
B. 4, 3, 2, 1
C. 3, 1, 4, 2
D. 2, 4, 1, 3
Answer: Option A
Solution (By Examveda Team)
Atmospheric pressure is inversely related to altitude — it decreases as elevation increases.Here is the correct order of the places in decreasing atmospheric pressure:
1. Mumbai (3) – Located at sea level, hence has the highest atmospheric pressure.
2. Delhi (4) – Situated in the plains at a moderate elevation, so pressure is slightly lower than Mumbai.
3. Shimla (1) – A hill station at a high altitude, so it has lower pressure than both Mumbai and Delhi.
4. Gangtok (2) – Located at a higher elevation than Shimla, thus has the lowest atmospheric pressure among the four.
Therefore, the correct decreasing order of atmospheric pressure is: 3 (Mumbai), 4 (Delhi), 1 (Shimla), 2 (Gangtok).
This Question Belongs to Geography >> Transportation System Of India
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The correct order from highest to lowest atmospheric pressure is Mumbai, Delhi, Shimla, and Gangtok. Here's why:
Mumbai:
Located near sea level, Mumbai experiences the highest atmospheric pressure among the four cities. Sea level air is denser and exerts more pressure on the surface.
Delhi:
Delhi is at a higher altitude than Mumbai but still relatively low compared to Shimla and Gangtok. Its atmospheric pressure will be lower than Mumbai but higher than Shimla and Gangtok.
Shimla:
Shimla is located in the Himalayas at a considerably higher altitude than Mumbai and Delhi. As altitude increases, the density of air decreases, and so does the atmospheric pressure.
Gangtok:
Gangtok is located even higher than Shimla in the Himalayas. This higher altitude results in the lowest atmospheric pressure of the four cities.
In simpler terms: Atmospheric pressure decreases as altitude increases. Cities at higher altitudes (like Shimla and Gangtok) have lower atmospheric pressure than cities at lower altitudes (like Mumbai and Delhi).