At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm.) and the gas behaves ideally.)
A. μ° + RT lnf
B. μ°+ R lnf
C. μ° + T lnf
D. μ° + $$\frac{{\text{R}}}{{\text{T}}}$$ lnf
Answer: Option A
Solution (By Examveda Team)
The chemical potential and fugacity of an real gas is related by :\[\mu = {\mu ^ \circ } + RT\frac{{lnf}}{{{f^ \circ }}}\]
Where \[{f^ \circ } = \] standard fugacity given $$=1$$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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