At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm.) and the gas behaves ideally.)

A. μ° + RT lnf

B. μ°+ R lnf

C. μ° + T lnf

D. μ° + $$\frac{{\text{R}}}{{\text{T}}}$$ lnf

Answer: Option A

Solution(By Examveda Team)

The chemical potential and fugacity of an real gas is related by :
\[\mu = {\mu ^ \circ } + RT\frac{{lnf}}{{{f^ \circ }}}\]
Where \[{f^ \circ } = \]   standard fugacity given $$=1$$