$${\bf{\hat A}}$$ and $${\bf{\hat B}}$$ represent two physical characteristics of a quantum system. If $${\bf{\hat A}}$$ is Hermitian, then for the product $${\bf{\hat A\hat B}}$$ to be Hermitian, it is sufficient that
A. $${\bf{\hat B}}$$ is Hermitian
B. $${\bf{\hat B}}$$ is anti-Hermitian
C. $${\bf{\hat B}}$$ is Hermitian and $${\bf{\hat A}}$$ and $${\bf{\hat B}}$$ commute
D. $${\bf{\hat B}}$$ is Hermitian and $${\bf{\hat A}}$$ and $${\bf{\hat B}}$$ anti-commute
Answer: Option C
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above

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