Answer & Solution
Answer: Option B
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72. What will be the output of the following C++ code?
#include<iostream>
using namespace std;
class Base {
public:
Base()
{ cout<<"Constructing Base \n"; }
~Base()
{ cout<<"Destructing Base \n"; }
};
class Derived: public Base {
public:
Derived()
{ cout<<"Constructing Derived \n"; }
~Derived()
{ cout<<"Destructing Derived \n"; }
};
int main(void)
{
Derived *d = new Derived();
Base *b = d;
delete b;
return 0;
}
#include<iostream>
using namespace std;
class Base {
public:
Base()
{ cout<<"Constructing Base \n"; }
~Base()
{ cout<<"Destructing Base \n"; }
};
class Derived: public Base {
public:
Derived()
{ cout<<"Constructing Derived \n"; }
~Derived()
{ cout<<"Destructing Derived \n"; }
};
int main(void)
{
Derived *d = new Derived();
Base *b = d;
delete b;
return 0;
}73. C++ is . . . . . . . .
74. What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class A{
public:
A(){
cout<<"Constructor called\n";
}
~A(){
cout<<"Destructor called\n";
}
};
int main(int argc, char const *argv[])
{
A *a = new A[5];
delete[] a;
return 0;
}
#include <iostream>
using namespace std;
class A{
public:
A(){
cout<<"Constructor called\n";
}
~A(){
cout<<"Destructor called\n";
}
};
int main(int argc, char const *argv[])
{
A *a = new A[5];
delete[] a;
return 0;
}75. How compile-time polymorphisms are implemented in C++?
76. What does modularity mean?
77. How many types of polymorphism are there in C++?
78. Which of the following shows multiple inheritances?
79. What happens if a pointer is deleted twice in a program as shown in the following C++ statements?
int *ptr = new int;
delete ptr;
delete ptr;
int *ptr = new int;
delete ptr;
delete ptr;