Answer & Solution
Answer: Option C
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62. What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int a = 5;
int *p = &a;
int *(&q) = p;
cout<<q;
return 0;
}
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int a = 5;
int *p = &a;
int *(&q) = p;
cout<<q;
return 0;
}63. Which one of the following is not a possible state for a pointer.
64. Which value can we not assign to reference?
65. What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int f(int &x, int c)
{
c = c - 1;
if (c == 0) return 1;
x = x + 1;
return f(x, c) * x;
}
int main(int argc, char const *argv[])
{
int a = 4;
cout<<f(a,a);
return 0;
}
#include <iostream>
using namespace std;
int f(int &x, int c)
{
c = c - 1;
if (c == 0) return 1;
x = x + 1;
return f(x, c) * x;
}
int main(int argc, char const *argv[])
{
int a = 4;
cout<<f(a,a);
return 0;
}66. What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int &q = NULL;
cout<<q;
return 0;
}
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int &q = NULL;
cout<<q;
return 0;
}67. Which reference modifier is used to define the reference variable?
68. The operator used for dereferencing or indirection is . . . . . . . .
69. What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int &q = 5;
cout<<q;
return 0;
}
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
int main(int argc, char const *argv[])
{
int &q = 5;
cout<<q;
return 0;
}