Co-efficient of performance for a reversed Carnot cycle working between temperatures T₁ and T₂ (T₁ > T₂) is

A. $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$

B. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$

C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$

D. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_2}}}$$

Answer: Option A

Solution(By Examveda Team)

The reverse of heat engine is nothing but refrigerator coefficient of performance is given as $$COP = \frac{{{T_2}}}{{{T_1} - {T_2}}}$$