Co-efficient of performance for a reversed Carnot cycle working between temperatures T1 and T2 (T1 > T2) is
A. $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$
B. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_1} - {{\text{T}}_2}}}$$
C. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$
D. $$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_2}}}$$
Answer: Option A
Solution (By Examveda Team)
The reverse of heat engine is nothing but refrigerator coefficient of performance is given as $$COP = \frac{{{T_2}}}{{{T_1} - {T_2}}}$$This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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