Comment on the output of the following C code.
#include <stdio.h>
int main()
{
int a = 10;
int **c -= &&a;
}
#include <stdio.h>
int main()
{
int a = 10;
int **c -= &&a;
}A. You cannot apply any arithmetic operand to a pointer
B. We don't have address of an address operator
C. We have address of an address operator
D. None of the mentioned
Answer: Option B
Related Questions on Pointer
In C, what is a pointer primarily used for?
A. Decision making
B. Code organization
C. Variable declaration
D. Storing values
In C, how do you declare a pointer variable that can store the address of an integer?
A. int *ptr;
B. ptr int;
C. int ptr;
D. ptr *int;
What is the purpose of the '->' operator in C when used with pointers?
A. Arithmetic operation
B. Indirection operator
C. Member access operator
D. Bitwise operation
Join The Discussion