Consider the combined system of proton and electron in the hydrogen atom in its (electronic) ground state. Let $$I$$ denotes the quantum number associated with the total angular momentum and let \[ < \mathfrak{M} > \] denote the magnitude of the expectation value of the net magnetic moment in the state. Which of the following pairs represents a possible state of the system (\[{\mu _B}\] is Bohr magneton)?
A. \[I = 0,\, < \mathfrak{M} > = 0\]
B. \[I = \frac{1}{2},\, < \mathfrak{M} > = 1{\mu _B}\]
C. \[I = 1,\, < \mathfrak{M} > \approx 1{\mu _B}\]
D. \[I = 0,\, < \mathfrak{M} > = 2{\mu _B}\]
Answer: Option A
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above

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