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Consider the differential equation $$\frac{{{d^2}x}}{{d{t^2}}} + 2\frac{{dx}}{{dt}} + x = 0$$
At time t = 0, it is given that x = 1 and $$\frac{{dx}}{{dt}} = 0.$$  At t = 1, the value of x is given by

Answer & Solution
Correct Answer: Option B
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