Consider the following code snippet :
var a = [];
a.unshift(1);
a.unshift(22);
a.shift();
a.unshift(3,[4,5]);
a.shift();
a.shift();
a.shift();
The final output for the shift() is
var a = [];
a.unshift(1);
a.unshift(22);
a.shift();
a.unshift(3,[4,5]);
a.shift();
a.shift();
a.shift();
A. 1
B. [4,5]
C. [3,4,5]
D. Exception is thrown
Answer: Option A
Solution(By Examveda Team)
The unshift() and shift() methods behave much like push() and pop(), except that they insert and remove elements from the beginning of an array rather than from the end. unshift() adds an element or elements to the beginning of the array, shifts the existing array elements up to higher indexes to make room, and returns the new length of the array. shift() removes and returns the first element of the array, shifting all subsequent elements down one place to occupy the newly vacant space at the start of the array.This Question Belongs to Javascript >> Array And Function
Consider the code snippet given below
var count = [1,,3];
A. The omitted value takes “undefined”
B. This results in an error
C. This results in an exception
D. None of the mentioned
A. true false
B. false true
C. true true
D. false true
The pop() method of the array does which of the following task ?
A. decrements the total length by 1
B. increments the total length by 1
C. prints the first element but no effect on the length
D. None of the mentioned
Consider the following code snippet :
if (!a[i]) continue ;
A. Skips the undefined elements
B. Skips the non existent elements
C. Skips the null elements
D. All of the mentioned
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