Consider the following instructions executed in 8086.
PUSH AX; AX has 20 Hex in it
PUSH BX; BX has 34 Hex in it
POP AX;
ADD AX, BX;
POP G
The value stored in G would be
A. 20 Hex
B. 34 Hex
C. 54 Hex
D. 68 Hex
Answer: Option A
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