Consider the following recursive implementation to find the nth fibonnaci number:
int fibo(int n)
{
if(n == 1)
return 0;
else if(n == 2)
return 1;
return fibo(n - 1) + fibo(n - 2);
}
int main()
{
int n = 5;
int ans = fibo(n);
printf("%d",ans);
return 0;
}
Which of the following is the base case?
int fibo(int n)
{
if(n == 1)
return 0;
else if(n == 2)
return 1;
return fibo(n - 1) + fibo(n - 2);
}
int main()
{
int n = 5;
int ans = fibo(n);
printf("%d",ans);
return 0;
}A. if(n == 1)
B. else if(n == 2)
C. return fibo(n - 1) + fibo(n - 2)
D. both if(n == 1) and else if(n == 2)
Answer: Option D
This Question Belongs to Data Structure >> Miscellaneous On Data Structures
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