Consider the following series:
A B C D .... X Y Z | Y X ...... B A | B C D ...... Y Z | Y X ..... C B A | B C ........ Y Z ....
Which letter occupies the 1000th positing in the above series ?
A. B
B. C
C. X
D. Y
Answer: Option A
Solution (By Examveda Team)
We have 3 patterns:I: A B C D ... X Y Z, which occurs only once.
Y X ... B A, which repeats alternately.
B C ... Y Z, which repeats alternately.
Now, I: has 26 terms.
So, number of terms before the desired term = (999 - 26) = 973.
Each of the patterns which occurs after I: has 25 letters.
Now, 973 ÷ 25 gives quotient = 38 and remainder = 23.
Thus, the 1000th trem of the given series is the 24th term of the 39th pattern after I:.
Clearly, the 39th pattern is II: and its 24th term is B.
This Question Belongs to Competitive Reasoning >> Series Completion
Join The Discussion
Comments (1)
Related Questions on Series Completion
First there are 26 letters than 25 again 25 and so on.. keeping the first 26 letters aside we start from next 25 letters ( which are in reverse order ) the next 25( same order ) and we do this 25 till 38 times = 950 letters now adding the 26 letters = 976 letters . We want 1000th letter so remaining 24 letters . So the letter should be the 24th letter from the reverse order I.e B .