Consider the following series:
A B C D .... X Y Z | Y X ...... B A | B C D ...... Y Z | Y X ..... C B A | B C ........ Y Z ....
Which letter occupies the 1000th positing in the above series ?
A. B
B. C
C. X
D. Y
Answer: Option A
Solution(By Examveda Team)
We have 3 patterns:I: A B C D ... X Y Z, which occurs only once.
Y X ... B A, which repeats alternately.
B C ... Y Z, which repeats alternately.
Now, I: has 26 terms.
So, number of terms before the desired term = (999 - 26) = 973.
Each of the patterns which occurs after I: has 25 letters.
Now, 973 ÷ 25 gives quotient = 38 and remainder = 23.
Thus, the 1000th trem of the given series is the 24th term of the 39th pattern after I:.
Clearly, the 39th pattern is II: and its 24th term is B.
This Question Belongs to Competitive Reasoning >> Series Completion
Join The Discussion
Comments ( 1 )
Related Questions on Series Completion
First there are 26 letters than 25 again 25 and so on.. keeping the first 26 letters aside we start from next 25 letters ( which are in reverse order ) the next 25( same order ) and we do this 25 till 38 times = 950 letters now adding the 26 letters = 976 letters . We want 1000th letter so remaining 24 letters . So the letter should be the 24th letter from the reverse order I.e B .