Examveda

Consider the following three independent cases:
i. Particle A of charge +q moves in free space with a constant velocity $$\overrightarrow {\bf{v}} $$ (v ≪ speed of light).
ii. Particle B of charge +q moves in free space in a circle of radius R with same speed v as In case i.
iii. Particle C having charge -q moves as in case ii.
If the powers radiated by A, B and C are PA, PB and PC respectively then

A. PA = 0, PB > PC

B. PA = 0, PB = PC

C. PA > PB > PC

D. PA = PB = PC

Answer: Option B


This Question Belongs to Engineering Physics >> Electromagnetic Theory

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