Consider the pseudo code:
int avl(binarysearchtree root):
if(not root)
return 0
left_tree_height = avl(left_of_root)
if(left_tree_height== -1)
return left_tree_height
right_tree_height= avl(right_of_root)
if(right_tree_height==-1)
return right_tree_height
Does the above code can check if a binary search tree is an AVL tree?
int avl(binarysearchtree root):
if(not root)
return 0
left_tree_height = avl(left_of_root)
if(left_tree_height== -1)
return left_tree_height
right_tree_height= avl(right_of_root)
if(right_tree_height==-1)
return right_tree_heightA. yes
B. no
Answer: Option A
This Question Belongs to Data Structure >> Binary Search Trees(B Tree)
Related Questions on Binary Search Trees(B Tree)
A. O(1)
B. O(log n)
C. O(n)
D. O(n log n)
Which traversal method of a BST will produce a sorted sequence of node values?
A. Inorder
B. Preorder
C. Postorder
D. Level-order
What is the maximum number of children a node in a Binary Search Tree (BST) can have?
A. 1
B. 2
C. 3
D. Any number
How can you determine if a Binary Tree is a Binary Search Tree (BST)?
A. Verify if all nodes in the left subtree are less than the root and all nodes in the right subtree are greater than the root.
B. Check if the tree is balanced.
C. Ensure all nodes have exactly two children.
D. Verify the height of the tree.
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