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Direction (1 - 5): Study the pie-chart given below carefully and answer the questions that follow.
Percentage-wise break up of students in terms of specialization in M.B.A.
Total Number of students = 8000.
Direction image of Pie Chart chapter
1
Students having IB as specialisation forms approximately what percent of students having Marketing as specialisation?
Discuss
Answer & Solution
Number of students in various specialisations:
$$\eqalign{ & \text{IB → } \frac{19}{100}\times8000 = 1520 \cr & \text{IR → } \frac{16}{100}\times8000 = 1280 \cr & \text{Finance → } \frac{12}{100}\times8000 = 960 \cr & \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr & \text{IT → } \frac{17}{100}\times8000 = 1360 \cr & \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$

$$\eqalign{ & \text{Required percentage} \cr & = \left(\frac{1520}{1760}\times100\right)\% \cr & = \frac{950}{11}\% \cr & = 86.36\% \cr & \approx 86\% \cr} $$
2
Students having IR as specialisation forms approximately what percent of students having HR as specialisation?
Discuss
Answer & Solution
Number of students in various specialisations:
$$\eqalign{ & \text{IB → } \frac{19}{100}\times8000 = 1520 \cr & \text{IR → } \frac{16}{100}\times8000 = 1280 \cr & \text{Finance → } \frac{12}{100}\times8000 = 960 \cr & \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr & \text{IT → } \frac{17}{100}\times8000 = 1360 \cr & \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$

$$\eqalign{ & \text{Required percentage} \cr & = \left(\frac{1280}{1120}\times100\right)\% \cr & = \frac{800}{7}\% \cr & = 114.28\% \cr & \approx 114\% \cr} $$
3
What is the total number of students having IB as specialisation?
Discuss
Answer & Solution
Number of students in various specialisations:
$$\eqalign{ & \text{IB → } \frac{19}{100}\times8000 = 1520 \cr & \text{IR → } \frac{16}{100}\times8000 = 1280 \cr & \text{Finance → } \frac{12}{100}\times8000 = 960 \cr & \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr & \text{IT → } \frac{17}{100}\times8000 = 1360 \cr & \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$

Number of those having IB as specialisation = 1520
4
What is the total number of students having specialisation in IR, marketing and IT?
Discuss
Answer & Solution
Number of students in various specialisations:
$$\eqalign{ & \text{IB → } \frac{19}{100}\times8000 = 1520 \cr & \text{IR → } \frac{16}{100}\times8000 = 1280 \cr & \text{Finance → } \frac{12}{100}\times8000 = 960 \cr & \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr & \text{IT → } \frac{17}{100}\times8000 = 1360 \cr & \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$

Required number of students
= 1280 + 1760 + 1360
= 4400
5
What is the ratio of the students having finance as specialisation to students having HR as specialisation?
Discuss
Answer & Solution
Number of students in various specialisations:
$$\eqalign{ & \text{IB → } \frac{19}{100}\times8000 = 1520 \cr & \text{IR → } \frac{16}{100}\times8000 = 1280 \cr & \text{Finance → } \frac{12}{100}\times8000 = 960 \cr & \text{Marketing → } \frac{22}{100}\times8000 = 1760 \cr & \text{IT → } \frac{17}{100}\times8000 = 1360 \cr & \text{HR → } \frac{14}{100}\times8000 = 1120 \cr} $$

$$\eqalign{ & \text{Required ratio} \cr & = \text{Finance : HR} \cr & = \frac{960}{1120} \cr & = \frac{6}{7} \cr & = 6:7\cr} $$