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Directions (1 - 5): Based on the data given on the pie-chart. Solve the questions which follow :

Percentage Sales of different models of Computers in Kolkata in two different years . Given total sales in 1998 is 7890 and increase 16.5% in 1999.

Direction image of Pie Chart chapter
Direction image of Pie Chart chapter
1
The percentage change in the sales of Toshiba in 1999 is approximately :
Discuss
Answer & Solution
Total sales in 1998 = 7890
Sales of Toshiba = 12%
= $$\frac{7890\times12}{100}$$
= 946.8
≈ 947

Total sales in 1999
= 7890 + (16.5% of 7890)
= 9191
Sales of Toshiba
= 8% of 9191
= 735

Change in sales
= 947 - 735
= 212
% change
= $$\frac{212\times100}{986}$$
= 21.5%
≈ 22%
2
Which brand of computers among those shown, exhibited the second highest rate of growth in two years and had less sales in 1999 than 1998?
Discuss
Answer & Solution
There is no percentage change in the given three company.
Thus, All of these is the correct answer.
3
What is the ratio between the Compaq sales in 1998 and those IBM in 1999?
Discuss
Answer & Solution
Sale of Compaq in 1998,
= 21%
= $$\frac{7890\times21}{100}$$
=1657

Sales of IBM in 1999,
= 17%
= $$\frac{9191\times17}{100}$$
= 1562

Ratio = $$\frac{1657}{1562}$$ = 1.06

We have calculated total sales in 1999 is 9191 in question no. 1.
4
For which brand of computers, did the sales increase the maximum in terms of absolute value between the two years?
Discuss
Answer & Solution
The maximum increase in sales is of Compaq which is 4%. Thus, it will got maximum absolute value too.
5
IBM's sales in 1998 is what percentage of the sales of Samsung in 1999?
Discuss
Answer & Solution
IBM's sales in 1998
= 17% of 7890
= 1341

Samsung sales in 1999
= 24% of 9191
= 2205

∴ Required answer
= $$\frac{1341}{2205}\times100$$
= 60.8%