91. Which of the following is a disadvantage of linear search?
92. What is the advantage of recursive approach than an iterative approach?
93. Which of the following is the most desirable condition for interpolation search?
94. Given delta[4] is a global array and number of elements in the sorted array is 10, what are the values in the delta array?
95. Which of the following false about Jump Search?
96. Which of the following is not an application of binary search?
97. In which of the following case jump search will be preferred over binary search?
98. The array is as follows: 1, 2, 3, 6, 8, 10. Given that the number 17 is to be searched. At which call it tells that there's no such element? (By using linear search(recursive) algorithm)
99. What will be the worst case time complexity of the following code?
#include<bits/stdc++.h>
using namespace std;
void func(char* str2, char* str1)
{
int m = strlen(str2);
int n = strlen(str1);
for (int i = 0; i <= n - m; i++)
{
int j;
for (j = 0; j < m; j++)
if (str1[i + j] != str2[j])
break;
if (j == m)
cout << i << endl;
}
}
int main()
{
char str1[] = "1253234";
char str2[] = "323";
func(str2, str1);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
void func(char* str2, char* str1)
{
int m = strlen(str2);
int n = strlen(str1);
for (int i = 0; i <= n - m; i++)
{
int j;
for (j = 0; j < m; j++)
if (str1[i + j] != str2[j])
break;
if (j == m)
cout << i << endl;
}
}
int main()
{
char str1[] = "1253234";
char str2[] = "323";
func(str2, str1);
return 0;
}100. What will be the best case time complexity of the following code?
#include<bits/stdc++.h>
using namespace std;
void func(char* str2, char* str1)
{
int m = strlen(str2);
int n = strlen(str1);
for (int i = 0; i <= n - m; i++)
{
int j;
for (j = 0; j < m; j++)
if (str1[i + j] != str2[j])
break;
if (j == m)
cout << i << endl;
}
}
int main()
{
char str1[] = "1253234";
char str2[] = "323";
func(str2, str1);
return 0;
}
#include<bits/stdc++.h>
using namespace std;
void func(char* str2, char* str1)
{
int m = strlen(str2);
int n = strlen(str1);
for (int i = 0; i <= n - m; i++)
{
int j;
for (j = 0; j < m; j++)
if (str1[i + j] != str2[j])
break;
if (j == m)
cout << i << endl;
}
}
int main()
{
char str1[] = "1253234";
char str2[] = "323";
func(str2, str1);
return 0;
}Read More Section(Searching Algorithms)
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