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Density of states of free electrons in a solid moving with an energy 0.1 eV is given by 2.15 × 1021 e/V cm-3. The density of states (in e/V cm-3) for electrons moving with an energy of 0.4 eV will be

A. 1.07 × 1021

B. 1.52 × 1021

C. 3.04 × 1021

D. 4.30 × 1021

Answer: Option D


This Question Belongs to Engineering Physics >> Solid State Physics

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In a cubic crystal, atoms of mass M1 lie on one set of planes and atoms of mass M2 lie on planes interleaved between those of the first set. If C is the forte constant between nearest neighbour planes, the frequency of lattice vibrations for the optical phonon branch with wave vector k = 0 is

A. $$\sqrt {2C\left( {\frac{1}{{{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

B. $$\sqrt {C\left( {\frac{1}{{2{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

C. $$\sqrt {C\left( {\frac{1}{{{M_1}}} + \frac{1}{{2{M_2}}}} \right)} $$

D. zero