Determine Output:

#include<stdio.h>
void main()
{
      int *ptr, a=10;
      ptr = &a;
      *ptr += 1;
      printf("%d, %d", *ptr, a);
}

Solution (By Examveda Team)

Address of variable a is assigned to the integer pointer ptr.
Due to the statement;
*ptr += 1;
value at address pointing by ptr incremented by 1.
As the value at address is changed so variable a also get the updated value.