Determine the bandwidth of the FM signal for 5kHz audio signal modulated by a carrier of 50 MHz causing a frequency deviation of 25 kHz?
A. 60 kHz
B. 90 kHz
C. 30 kHz
D. 80 kHz
Answer: Option A
Solution (By Examveda Team)
In Frequency Modulation (FM), the bandwidth of the signal is determined by Carson's Rule.Carson's Rule states: Bandwidth (BW) ≈ 2 * (Δf + fm), where:
Δf is the frequency deviation, which is 25 kHz in this case.
fm is the highest frequency in the modulating signal, which is 5 kHz in this case.
Plugging in the values: BW ≈ 2 * (25 kHz + 5 kHz).
BW ≈ 2 * (30 kHz).
BW ≈ 60 kHz.
Therefore, the bandwidth of the FM signal is approximately 60 kHz.
This Question Belongs to Electronics And Communications Engineering >> Communication Systems
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According to Carson rule signal, BW is given as:
B.W = (β + 1) 2fm
B.W. = 2[Δf + fm]
If multiple frequencies are available in modulating signal then,
B.W. = 2(β + 1) fmax