?
Determine the bandwidth of the FM signal for 5kHz audio signal modulated by a carrier of 50 MHz causing a frequency deviation of 25 kHz?
Answer & Solution
Correct Answer:
Option
A
In Frequency Modulation (FM), the bandwidth of the signal is determined by Carson's Rule.
Carson's Rule states: Bandwidth (BW) ≈ 2 * (Δf + fm), where:
Δf is the frequency deviation, which is 25 kHz in this case.
fm is the highest frequency in the modulating signal, which is 5 kHz in this case.
Plugging in the values: BW ≈ 2 * (25 kHz + 5 kHz).
BW ≈ 2 * (30 kHz).
BW ≈ 60 kHz.
Therefore, the bandwidth of the FM signal is approximately 60 kHz.
Carson's Rule states: Bandwidth (BW) ≈ 2 * (Δf + fm), where:
Δf is the frequency deviation, which is 25 kHz in this case.
fm is the highest frequency in the modulating signal, which is 5 kHz in this case.
Plugging in the values: BW ≈ 2 * (25 kHz + 5 kHz).
BW ≈ 2 * (30 kHz).
BW ≈ 60 kHz.
Therefore, the bandwidth of the FM signal is approximately 60 kHz.
Join the Discussion
Login to post a comment or share your explanation.
LoginB.W = (β + 1) 2fm
B.W. = 2[Δf + fm]
If multiple frequencies are available in modulating signal then,
B.W. = 2(β + 1) fmax