During Joule-Thomson expansion of gases

A. Enthalpy remains constant

B. Entropy remains constant

C. Temperature remains constant

D. None of these

Answer: Option A

Solution(By Examveda Team)

During, joule-thomson effect basically the change in internal (inter-molecular) energy and change in pressure energy will be equal to zero hence, enthalpy will remain constant.
$$\eqalign{ & dU + d\left( {PV} \right) = 0 \cr & \Rightarrow d\left( {U + PV} \right) = 0 \cr & \Rightarrow d\left( H \right) = 0 \cr & {\text{or }}H = {\text{constant}}{\text{.}} \cr} $$