During Joule-Thomson expansion of gases
A. Enthalpy remains constant
B. Entropy remains constant
C. Temperature remains constant
D. None of these
Answer: Option A
Solution (By Examveda Team)
During, joule-thomson effect basically the change in internal (inter-molecular) energy and change in pressure energy will be equal to zero hence, enthalpy will remain constant.$$\eqalign{ & dU + d\left( {PV} \right) = 0 \cr & \Rightarrow d\left( {U + PV} \right) = 0 \cr & \Rightarrow d\left( H \right) = 0 \cr & {\text{or }}H = {\text{constant}}{\text{.}} \cr} $$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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