Each of the circles of equal radii with centres A and B pass through the centre of one another. They cut at C and D then ∠DBC is equal to?
A. 60°
B. 100°
C. 120°
D. 140°
Answer: Option C
Solution (By Examveda Team)
According to question
AB = AD = DB = r
∴ ΔADB is a equilateral triangle
∠DBA = 60°
Similar in ΔABC
∠ABC = 60°
∠DBC = 60° + 60°
∴ ∠DBC = 120°
This Question Belongs to Arithmetic Ability >> Geometry
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