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Efficiency of a Carnot engine working between temperatures T1 and T2 (T1 < T2) is
Answer & Solution
Correct Answer:
Option
A
Here the question should be read carefully given $$\left( {{T_1} < {T_2}} \right)$$
So, the hot reservoir is $${{T_2}}$$ and cold reservoir is $${{T_1}}$$ hence the efficiency will be $$\aleph = 1 - \frac{{{T_1}}}{{{T_2}}}$$
So, the hot reservoir is $${{T_2}}$$ and cold reservoir is $${{T_1}}$$ hence the efficiency will be $$\aleph = 1 - \frac{{{T_1}}}{{{T_2}}}$$
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