Answer & Solution
Answer: Option A
Solution:
The bandwidth (
BW) of a resonant circuit can be calculated using the formula:
$$BW = \text{Upper Critical Frequency} - \text{Lower Critical Frequency}$$
In this case:
Lower Critical Frequency ($$f_1$$) = 7 kHz
Upper Critical Frequency ($$f_2$$) = 13 kHz
Now, we can calculate the bandwidth:
$$BW = f_2 - f_1 = 13 \, \text{kHz} - 7 \, \text{kHz} = 6 \, \text{kHz}$$
So, the bandwidth of the circuit is
6 kHz.
The correct answer is
Option A: 6 kHz.