## 1. Sucrose is converted to a mixture of glucose and fructose in a pseudo first order process under alkaline conditions. The reaction has a half-life of 28.4 min. The time required for the reduction of a 8.0 mM sample of sucrose to 1.0 mM is

## 2. At T = 300 K, the thermal energy [k_{B}T] in cm^{-1} is approximately

_{B}T] in cm

^{-1}is approximately

## 3. The half-life of a first order reaction varies with temperature according to

## 4. For a given first order reaction, the reactant reduces to $${\frac{1}{4}^{{\text{th}}}}$$ its initial value in 10 min. The rate constant of the reaction is

## 5. For the reaction, 2X_{3} $$ \rightleftharpoons $$ 3X_{2}, the rate of formation of X_{2} is

_{3}$$ \rightleftharpoons $$ 3X

_{2}, the rate of formation of X

_{2}is

## 6. The half-life time for a reaction at initial concentrations of 0.1 and 0.4 mol^{-1} are 200 s and 50 s respectively. The order of the reaction is

^{-1}are 200 s and 50 s respectively. The order of the reaction is

## 7. For the reaction shown below,

the value of k_{1} is 1 × 10^{-4} s^{-1}. If the reaction starts from X, the ratio of the concentrations of Y and Z at any given time during the course of the reaction is found to be $$\frac{{\left[ {\text{Y}} \right]}}{{\left[ {\text{Z}} \right]}} = \frac{1}{4}.$$ The value of k_{2} is

the value of k

_{1}is 1 × 10

^{-4}s

^{-1}. If the reaction starts from X, the ratio of the concentrations of Y and Z at any given time during the course of the reaction is found to be $$\frac{{\left[ {\text{Y}} \right]}}{{\left[ {\text{Z}} \right]}} = \frac{1}{4}.$$ The value of k

_{2}is

## 8. Consider an exothermic reaction, $$A\mathop {\mathop \rightleftharpoons \limits_{{k_{ - 1}}} }\limits^{{k_1}} I$$

As the temperature increases

As the temperature increases

## 9. 1 g of ^{90}Sr gets converted to 0.953 g after 2 yr. The half-life of ^{90}Sr, and the amount of ^{90}Sr remaining after 5 yr are

^{90}Sr gets converted to 0.953 g after 2 yr. The half-life of

^{90}Sr, and the amount of

^{90}Sr remaining after 5 yr are

## 10. The reaction, 2NO(g) + O_{2}(g) → 2NO_{2}(g) proceeds via the following steps:

NO + NO \[\xrightarrow{{{{\text{K}}_{\text{a}}}}}\] N_{2}O_{2}

N_{2}O_{2} \[\xrightarrow{{{{\text{K}}_{{\text{a'}}}}}}\] NO + NO

N_{2}O_{2} + O_{2} \[\xrightarrow[{\left( {{\text{slow}}} \right)}]{{{{\text{k}}_{\text{b}}}}}\] NO_{2} + NO_{2}

The rate of this reaction is equal to

_{2}(g) → 2NO

_{2}(g) proceeds via the following steps:

NO + NO \[\xrightarrow{{{{\text{K}}_{\text{a}}}}}\] N

_{2}O

_{2}

N

_{2}O

_{2}\[\xrightarrow{{{{\text{K}}_{{\text{a'}}}}}}\] NO + NO

N

_{2}O

_{2}+ O

_{2}\[\xrightarrow[{\left( {{\text{slow}}} \right)}]{{{{\text{k}}_{\text{b}}}}}\] NO

_{2}+ NO

_{2}

The rate of this reaction is equal to