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Enthalpy of a gas depends upon its
Answer & Solution
Correct Answer:
Option
A
Because the enthalpy of an real gas is given by
$$dH = {C_p}dT + \left[ {V - T\left( {\frac{{\partial V}}{{\partial T}}} \right)}p \right]dp$$
For ideal gas since $$\left( {\frac{{\partial V}}{{\partial T}}} \right)p = \frac{R}{P} \Rightarrow dH = {c_p}dT$$
Hence only for an ideal gas enthalpy is a function of temperature.
$$dH = {C_p}dT + \left[ {V - T\left( {\frac{{\partial V}}{{\partial T}}} \right)}p \right]dp$$
For ideal gas since $$\left( {\frac{{\partial V}}{{\partial T}}} \right)p = \frac{R}{P} \Rightarrow dH = {c_p}dT$$
Hence only for an ideal gas enthalpy is a function of temperature.
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