Entropy of an ideal gas depends upon its

A. Pressure

B. Temperature

C. Both A & B

D. Neither A nor B

Answer: Option C

Solution(By Examveda Team)

Entropy of an ideal gas depends upon :
\[\Delta S = \int_{{T_i}}^{{T_f}} {\frac{{{C_P}dT}}{T} - nRln\left( {\frac{{{P_f}}}{{{P_i}}}} \right)} \]
\[ \Rightarrow \] it depends upon both temperature and pressure.