For a cavity resonator with, Q0 = unloaded Q and ρ = standing wave ratio, Qe = the loaded Q is given by
A. $${Q_e} = \rho {Q_0}$$
B. $${Q_e} = \frac{{\rho + 1}}{\rho }{Q_0}$$
C. $${Q_e} = \frac{\rho }{{\rho + 1}}{Q_0}$$
D. $${Q_e} = \frac{1}{\rho }{Q_0}$$
Answer: Option C
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