For a constant value of coefficient of lateral friction, the value of required super-elevation increases with

Correct answer is C
Concept:

The general equation of superelevation is given by,



Where,

e = rate of superelevation = tan θ

R = radius of the horizontal curve in m

f = coefficient of lateral friction = 0.15

Equilibrium superelevation:

It is that superelevation which when provided imposes equal pressure on both outsides and inside of tyres of the vehicle, i.e f = 0

The rate of equilibrium superelevation on a road is given by



Explanation:

The rate of equilibrium superelevation on a road is given by



For a constant value of co-efficient of lateral friction:

e α V2 i.e The rate of equilibrium superelevation on a road is directly proportional to the square of the velocity.

e α 1/R i.e The rate of equilibrium superelevation on a road is inversely proportional to the radius of the horizontal curve.

C is correct. Since, e + f = v^2/gR

C

C is corecct ans.
e+f=v2/127R

Opp c is correct

It's wrong

C is the right answer

C is the right answer

C is correct

C

C

C correct answer

C correct answer

C is correct 1

e+f=v²/127R...so value of superelevation increases with increase in velocity and decrease in radius of curve
Option C is correct

I think C should be the ans

Ans. C as e+f=V^2/225R

Please explain the Answer for this question.... For constant lateral friction, e increases with decrease in speed and increase in radius