For a constant value of coefficient of lateral friction, the value of required super-elevation increases with
A. increase in both speed and radius of curve
B. decrease in both speed and radius of curve
C. increase in speed and with decrease in radius of curve
D. decrease in speed and with increase in radius of curve
Answer: Option D
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Highway facilities are designed for
A. annual average hourly volume
B. annual average daily traffic
C. thirtieth highest hourly volume
D. peak hourly volume of the year
The provision of traffic signals at intersections
A. reduces right angled and rear end collisions
B. increases right angled and rear end collisions
C. reduces right angled collisions but may increase rear end collisions
D. reduces rear end collisions but may increase right angled collisions
In CBR test the value of CBR is calculated at
A. 2.5 mm penetration only
B. 5.0 mm penetration only
C. 7.5 mm penetration only
D. both 2.5 mm and 5.0 mm penetrations
If aggregate impact value is 20 to 30 percent, then it is classified as
A. exceptionally strong
B. strong
C. satisfactory for road surfacing
D. unsuitable for road surfacing
Correct answer is C
Concept:
The general equation of superelevation is given by,
Where,
e = rate of superelevation = tan θ
R = radius of the horizontal curve in m
f = coefficient of lateral friction = 0.15
Equilibrium superelevation:
It is that superelevation which when provided imposes equal pressure on both outsides and inside of tyres of the vehicle, i.e f = 0
The rate of equilibrium superelevation on a road is given by
Explanation:
The rate of equilibrium superelevation on a road is given by
For a constant value of co-efficient of lateral friction:
e α V2 i.e The rate of equilibrium superelevation on a road is directly proportional to the square of the velocity.
e α 1/R i.e The rate of equilibrium superelevation on a road is inversely proportional to the radius of the horizontal curve.
C is correct. Since, e + f = v^2/gR
C
C is corecct ans.
e+f=v2/127R
Opp c is correct
It's wrong
C is the right answer
C is the right answer
C is correct
C
C
C correct answer
C correct answer
C is correct 1
e+f=v²/127R...so value of superelevation increases with increase in velocity and decrease in radius of curve
Option C is correct
I think C should be the ans
Ans. C as e+f=V^2/225R
Please explain the Answer for this question.... For constant lateral friction, e increases with decrease in speed and increase in radius