For a particle of mass m in a one-dimensional harmonic oscillator potential of the form $${V_{\left( x \right)}} = \frac{1}{2}m{\omega ^2}{x^2},$$ the first excited energy eigen state is $$\psi \left( x \right) = x{e^{ - a{x^2}}}.$$ The value of a is
A. $$\frac{{m\omega }}{{4\hbar }}$$
B. $$\frac{{m\omega }}{{3\hbar }}$$
C. $$\frac{{m\omega }}{{2\hbar }}$$
D. $$\frac{{2m\omega }}{{3\hbar }}$$
Answer: Option C
Join The Discussion