For a perfect free electron gas in a metal the magnitudes of phase velocity (vp) and group velocity (vg) are such that
A. vp = vg
B. vp = $$\frac{1}{2}$$vg
C. vp = $$\sqrt 2 $$ vg
D. vp = 2vg
Answer: Option A
A. vp = vg
B. vp = $$\frac{1}{2}$$vg
C. vp = $$\sqrt 2 $$ vg
D. vp = 2vg
Answer: Option A
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above
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